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An expression for oscillating electric field in a plane electromagnetic wave is given as Ez = 300 sin(5π × 103x - 3π × 1011t)Vm-1 Then, the value of magnetic field amplitude will be -

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Question

An expression for oscillating electric field in a plane electromagnetic wave is given as Ez = 300 sin(5π × 103x - 3π × 1011t)Vm-1 Then, the value of magnetic field amplitude will be ______. (Given: speed of light in Vacuum c = 3 × 108 ms-1)

Options

  • 1 × 10-6 T

  • 5 × 10-6 T

  • 18 × 109 T

  • 21 × 109 T

MCQ
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Solution

An expression for oscillating electric field in a plane electromagnetic wave is given as Ez = 300 sin(5π × 103x - 3π × 1011t)Vm-1 Then, the value of magnetic field amplitude will be 5 × 10-6 T. (Given: speed of light in Vacuum c = 3 × 108 ms-1)

Explanation:

We know that, 

B0 = `"E"_0/"V"=300/("w"/"k")`

= `(300xx5pixx10^3)/(3pixx10^11)`

= 5 × 10-6 T

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