Advertisements
Advertisements
प्रश्न
An ideal gas having pressure p, volume V and temperature T undergoes a thermodynamic process in which dW = 0 and dQ < 0. Then, for the gas ______.
विकल्प
p may increase or decrease.
T will decrease.
V will increase.
T will increase.
MCQ
रिक्त स्थान भरें
उत्तर
An ideal gas having pressure p, volume V and temperature T undergoes a thermodynamic process in which dW = 0 and dQ < 0. Then, for the gas T will decrease.
Explanation:
According to the first law of thermodynamics,
ΔU = ΔQ - dW
It is given that, dW = 0 and ΔQ < 0
Thus, ΔU = CvdT = ΔQ is negative.
Since, Cv is specific heat, which remains constant, the temperature will decrease.
shaalaa.com
First Law of Thermodynamics
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?