हिंदी

An ideal gas having pressure p, volume V and temperature T undergoes a thermodynamic process in which dW = 0 and dQ < 0. Then, for the gas ______. -

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प्रश्न

An ideal gas having pressure p, volume V and temperature T undergoes a thermodynamic process in which dW = 0 and dQ < 0. Then, for the gas ______.

विकल्प

  • p may increase or decrease.

  • T will decrease.

  • V will increase.

  • T will increase.

MCQ
रिक्त स्थान भरें

उत्तर

An ideal gas having pressure p, volume V and temperature T undergoes a thermodynamic process in which dW = 0 and dQ < 0. Then, for the gas T will decrease.

Explanation:

According to the first law of thermodynamics,

ΔU = ΔQ - dW

It is given that, dW = 0 and ΔQ < 0

Thus, ΔU = CvdT = ΔQ is negative.

Since, Cv is specific heat, which remains constant, the temperature will decrease.

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First Law of Thermodynamics
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