Question

An ideal gas having pressure p, volume V and temperature T undergoes a thermodynamic process in which dW = 0 and dQ < 0. Then, for the gas ______.

Options

• p may increase or decrease.

• T will decrease.

• V will increase.

• T will increase.

Answer 1

An ideal gas having pressure p, volume V and temperature T undergoes a thermodynamic process in which dW = 0 and dQ < 0. Then, for the gas T will decrease.

Explanation:

According to the first law of thermodynamics,

ΔU = ΔQ - dW

It is given that, dW = 0 and ΔQ < 0

Thus, ΔU = C_vdT = ΔQ is negative.

Since, C_v is specific heat, which remains constant, the temperature will decrease.