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प्रश्न
An object undergoes an acceleration of 8 ms-2 starting from rest. Find the distance travelled in 5 seconds.
उत्तर
Initial velocity of the object = 0 ms-1
Acceleration of the object = 8 ms-2.
Time = 5 s.
Distance covered would be S = ut + 1/2 at2.
S = 1/2 X 8 X 5 X5 = 100 m.
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