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प्रश्न
An object was launched from a place P in constant speed to hit a target. At the 15th second, it was 1400 m from the target, and at the 18th second 800 m away. Find the distance covered by it in 15 seconds
उत्तर
Let us take the time T along the x-axis and the Distance D along the y-axis.
Given when time T = 15s, the distance D = 1400 m
The corresponding point is (15, 1400)
Also when time T = 18s, the distance D = 800 m.
The corresponding point is (18, 800)
The distance covered by it in 15 seconds:
Put T = 15 in the above equation
15 = `(1400 - "D")/200 + 15`
∴ `(1400 - "D")/200` = 0
⇒ D = 1400 m.
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