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प्रश्न
Answer in brief.
[CoCl4]2- is a tetrahedral complex. Draw its box orbital diagram. State which orbitals participate in hybridization.
उत्तर
i. Box orbital diagram of [CoCl4]2–
ii. One 4s and three 4p orbitals participate in hybridization.
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\[\ce{[Ni(Cl)4]^{2-}}\]
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\[\ce{[Ni(CN)4]^2-}\]
