हिंदी

Apoorv throws two dice once and computes the product of the numbers appearing on the dice. Peehu throws one die and squares the number that appears on it. Who has the better chance of getting the - Mathematics

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प्रश्न

Apoorv throws two dice once and computes the product of the numbers appearing on the dice. Peehu throws one die and squares the number that appears on it. Who has the better chance of getting the number 36? Why?

योग

उत्तर

Apoorv throws two dice once.

So total number of outcomes = 36

Number of outcomes for getting product 36 = 1(6 × 6)

∴ Probability for Apoov = `1/36`

Also, Peehu throws one die

So, total number of outcomes = 6

Number of outcomes for getting square 36 = 1(62 = 36)

∴ Probability for Peehu = `1/6 = 6/36`

Hence, Peehu has better chance of getting the number 36.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 13: Statistics and Probability - Exercise 13.2 [पृष्ठ १६२]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 10
अध्याय 13 Statistics and Probability
Exercise 13.2 | Q 7 | पृष्ठ १६२
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