मराठी

Apoorv throws two dice once and computes the product of the numbers appearing on the dice. Peehu throws one die and squares the number that appears on it. Who has the better chance of getting the - Mathematics

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प्रश्न

Apoorv throws two dice once and computes the product of the numbers appearing on the dice. Peehu throws one die and squares the number that appears on it. Who has the better chance of getting the number 36? Why?

बेरीज

उत्तर

Apoorv throws two dice once.

So total number of outcomes = 36

Number of outcomes for getting product 36 = 1(6 × 6)

∴ Probability for Apoov = `1/36`

Also, Peehu throws one die

So, total number of outcomes = 6

Number of outcomes for getting square 36 = 1(62 = 36)

∴ Probability for Peehu = `1/6 = 6/36`

Hence, Peehu has better chance of getting the number 36.

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पाठ 13: Statistics and Probability - Exercise 13.2 [पृष्ठ १६२]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 10
पाठ 13 Statistics and Probability
Exercise 13.2 | Q 7 | पृष्ठ १६२

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