Question

Arrange 12.142, 12.124, 12.104, 12.401 and 12.214 in ascending order.

Answer 1

Given numbers are 12.142, 12.124, 12.104, 12.401 and 12.214

∴ 12.142 = `10 + 2 + 1/10 + 4/100 + 2/1000`

12.124 = `10 + 2 + 1/10 + 2/100 + 4/1000`

12.104 = `10 + 2 + 1/10 + 0/100 + 4/1000`

12.401 = `10 + 2 + 4/10 + 0/100 + 1/1000`

12.214 = `10 + 2 + 2/10 + 1/100 + 2/1000`

Here, whole part of all numbers are same and tenths part of 12.142, 12.124 and 12.104 are same.

Now, tenths part of 12.401 = `4/10`

And tenths partt of 12.214 = `2/10`

∵ `4/10 > 2/10`

∴ 12.401 > 12.214

Again, hundredths part of 12.142 = `4/10`

∴ Hundredths part of 12.124 = `2/100`

And hundredths part of 12.104 = `0/100`

∴ `4/100 > 2/100 > 0/100`

∴ 12.142 > 12.124 > 12.104

Hence, the ascending order of given number are 12.104 < 12.124 < 12.142 < 12.214 < 12.401.