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प्रश्न
Arrange 12.142, 12.124, 12.104, 12.401 and 12.214 in ascending order.
उत्तर
Given numbers are 12.142, 12.124, 12.104, 12.401 and 12.214
∴ 12.142 = `10 + 2 + 1/10 + 4/100 + 2/1000`
12.124 = `10 + 2 + 1/10 + 2/100 + 4/1000`
12.104 = `10 + 2 + 1/10 + 0/100 + 4/1000`
12.401 = `10 + 2 + 4/10 + 0/100 + 1/1000`
12.214 = `10 + 2 + 2/10 + 1/100 + 2/1000`
Here, whole part of all numbers are same and tenths part of 12.142, 12.124 and 12.104 are same.
Now, tenths part of 12.401 = `4/10`
And tenths partt of 12.214 = `2/10`
∵ `4/10 > 2/10`
∴ 12.401 > 12.214
Again, hundredths part of 12.142 = `4/10`
∴ Hundredths part of 12.124 = `2/100`
And hundredths part of 12.104 = `0/100`
∴ `4/100 > 2/100 > 0/100`
∴ 12.142 > 12.124 > 12.104
Hence, the ascending order of given number are 12.104 < 12.124 < 12.142 < 12.214 < 12.401.
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