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At what distance below the surface of the Earth, the acceleration due to gravity decreases by 10% of its value at the surface, given the radius of Earth is 6400 km. - Physics

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प्रश्न

At what distance below the surface of the Earth, the acceleration due to gravity decreases by 10% of its value at the surface, given the radius of Earth is 6400 km.

संख्यात्मक

उत्तर

Given: gd = 90% of g i.e., `"g"_"d"/"g"` = 0.9,
R = 6400 km = 6.4 × 106 m

To find: Distance below the Earth’s surface (d)

Formula: gd = `"g"(1 - "d"/"R")`

Calculation: From formula,

`"g"_"d"/"g" = (1 - "d"/"R")`

∴ `"d"/"R" = 1 - "g"_"d"/"g"`

∴ d = R`(1 - "g"_"d"/"g")`

= 6.4 × 106 × 0.1

= 640 × 103 m

= 640 km

At distance 640 km below the surface of the Earth, value of acceleration due to gravity decreases by 10%.

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Variation in the Acceleration Due to Gravity with Altitude, Depth, Latitude and Shape
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Gravitation - Exercises [पृष्ठ ९८]

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बालभारती Physics [English] 11 Standard Maharashtra State Board
अध्याय 5 Gravitation
Exercises | Q 4. (i) | पृष्ठ ९८

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