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प्रश्न
Atomic numbers of elements A, B, C, D, E, F are 8, 7, 11, 12, 13 and 9 respectively. State the type of ions they form.
उत्तर १
The electronic configurations of the given elements are:
A = 8 (2, 6)
B = 7 (2, 5)
C = 11 (2, 8, 1)
D = 12 (2, 8, 2)
E = 13 (2, 8, 3)
F = 9 (2, 7)
Thus A, B, F will form anions and C, D, E will form cations.
उत्तर २
Element | Atomic no. | Electronic configuration | Difference from Octet | Ion formed |
A | 8 | 2, 6 | 8 − 6 = 2 | −2 |
B | 7 | 2, 5 | 8 − 5 = 3 | −3 |
C | 11 | 2, 8, 1 | One electron more than octet | +1 |
D | 12 | 2, 8, 2 | Two electrons more than octet | +2 |
E | 13 | 2, 8, 3 | Three electrons more than octet | +3 |
F | 9 | 2, 7 | 8 − 7 | −1 |
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Group numbers |
IA | IIA | IIIA | IVA | VA | VIA | VIIA | O |
1 | 2 | 13 | 14 | 15 | 16 | 17 | 18 | |
Li | D | O | J | Ne | ||||
A | Mg | E | Si | H | K | |||
B | C | F | G | L |
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Group 1 |
Group 2 |
Group 17 |
Group 18 |
|
|
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D |
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B |
C |
|
A |
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E |
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