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प्रश्न
Balance the equation stepwise.
Ag(s) + HCl(aq) → AgCl ↓+ H2 ↑
उत्तर
Ag(s) + HCl(aq) → AgCl ↓+ H2 ↑
Step1. Count the number of each atom in reactant side:
H= 1
Ag=1
Cl=1
Step2. Count the number of each atom in product side:
H= 2
Ag=1
Cl=1
Step3.Then balance the number of each atom in an equation by multiplying reactant and product side with numeral value:
If we multiply Ag by 2 and HCl by 2 in the reactant side and AgCl by 2 in the product side, then number of atoms in product and reactant side gets balance.
2Ag(s) + 2HCl(aq) → 2AgCl ↓+ H2 ↑
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