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प्रश्न
Balance the following equation by the ion electron method.
\[\ce{C2O^2-_4 + Cr2O^2-_7 -> Cr^3+ + CO2}\] (in acid medium)
उत्तर
\[\ce{C^{+3}_2O^2-_4 -> C^{+4}O2}\] ......(1)
\[\ce{Cr^{+6}_2O^2-_7 -> Cr^3+}\] .......(2)
\[\ce{C2O^2-_4 -> 2CO2 + 2e^-}\] .....(3)
\[\ce{Cr2O^2-_7 + 14H^+ -> 2Cr^3+ + 7H2O}\] ......(4)
\[\ce{3C2O^2-_4 -> 6CO2 + 6e^-}\] ........(5) [Eq. (3) × 3]
\[\ce{Cr2O^2-_7 + 14H^+ + 6e^- -> 2Cr^3+ + 7H2O}\] .........(4)
\[\ce{Cr2O^2-_7 + 3C2O^2-_4 + 14H^+ -> 2Cr^3+ + 6CO2 + 7H2O}\]
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