Advertisements
Advertisements
प्रश्न
Below is the given frequency distribution of words in an essay
| Number of Words | Number of Candidates |
| 600 – 800 | 8 |
| 800 – 1000 | 22 |
| 1000 – 1200 | 40 |
| 1200 – 1400 | 18 |
| 1400 - 1600 | 12 |
Find the mean number of words written.
उत्तर
| (Number of words) | Class Mark | (Number of candidates) | fiXi |
| Class intervals | Xi | Frequency | |
| fi | |||
| 600 – 800 | 700 | 8 | 5600 |
| 800 – 1000 | 900 | 22 | 19800 |
| 1000 – 1200 | 1100 | 40 | 44000 |
| 1200 – 1400 | 1300 | 18 | 23400 |
| 1400 – 1600 | 1500 | 12 | 18000 |
| Total | ∑fi=100 | ∑fiXi=110800 |
Mean=
`barX=(Sigmaf_ix_i)/(Sigmaf_i)=110800/100=1108`
∴ Mean number of words written in an essay is 1108.
APPEARS IN
संबंधित प्रश्न
For a certain frequency distribution, the value of Mean is 101 and Median is 100. Find the value of Mode.
100 surnames were randomly picked up from a local telephone directory and the frequency distribution of the number of letters in the English alphabets in the surnames was obtained as follows:
| Number of letters | Number of surnames |
| 1 - 4 | 6 |
| 4 − 7 | 30 |
| 7 - 10 | 40 |
| 10 - 13 | 6 |
| 13 - 16 | 4 |
| 16 − 19 | 4 |
Determine the median number of letters in the surnames. Find the mean number of letters in the surnames? Also, find the modal size of the surnames.
The numbers 6, 8, 10, 12, 13 and x are arranged in an ascending order. If the mean of the observations is equal to the median, find the value of x
If the median of the following data is 32.5, find the missing frequencies.
| Class interval: | 0 - 10 | 10 - 20 | 20 - 30 | 30 - 40 | 40 - 50 | 50 - 60 | 60 - 70 | Total |
| Frequency: | f1 | 5 | 9 | 12 | f2 | 3 | 2 | 40 |
A student got the following marks in 9 questions of a question paper.
3, 5, 7, 3, 8, 0, 1, 4 and 6.
Find the median of these marks.
The weights (in kg) of 10 students of a class are given below:
21, 28.5, 20.5, 24, 25.5, 22, 27.5, 28, 21 and 24.
Find the median of their weights.
The median of the following data is 16. Find the missing frequencies a and b if the total of frequencies is 70.
| Class | 0 – 5 | 5 – 10 | 10 – 15 | 15 – 20 | 20 – 25 | 25 – 30 | 30 – 35 | 35 – 40 |
| Frequency | 12 | a | 12 | 15 | b | 6 | 6 | 4 |
The median of the following data is 50. Find the values of p and q, if the sum of all the frequencies is 90.
| Marks: | 20 -30 | 30-40 | 40-50 | 50-60 | 60-70 | 70-80 | 80-90 |
| Frequency: | P | 15 | 25 | 20 | q | 8 | 10 |
Mode and mean of a data are 12k and 15A. Median of the data is ______.
For the following distribution
| Marks | 0 - 10 | 10 - 20 | 20 - 30 | 30 - 40 | 40 - 50 |
| No. of Students | 3 | 9 | 13 | 10 | 5 |
the number of students who got marks less than 30 is?
The Median when it is given that mode and mean are 8 and 9 respectively, is ______.
Consider the data:
| Class | 65 – 85 | 85 – 105 | 105 – 125 | 125 – 145 | 145 – 165 | 165 – 185 | 185 – 205 |
| Frequency | 4 | 5 | 13 | 20 | 14 | 7 | 4 |
The difference of the upper limit of the median class and the lower limit of the modal class is:
The maximum bowling speeds, in km per hour, of 33 players at a cricket coaching centre are given as follows:
| Speed (km/h) | 85 – 100 | 100 – 115 | 115 – 130 | 130 – 145 |
| Number of players | 11 | 9 | 8 | 5 |
Calculate the median bowling speed.
|
Yoga is an ancient practice which is a form of meditation and exercise. By practising yoga, we not even make our body healthy but also achieve inner peace and calmness. The International Yoga Day is celebrated on the 21st of June every year since 2015.
|
| Age Group | 15 – 25 | 25 – 35 | 35 – 45 | 45 –55 | 55 –65 | 65 –75 | 75 – 85 |
| Number of People |
8 | 10 | 15 | 25 | 40 | 24 | 18 |
Based on the above, find the following:
- Find the median age of people enrolled for the camp.
- If x more people of the age group 65 – 75 had enrolled for the camp, the mean age would have been 58. Find the value of x.
The empirical relation between the mode, median and mean of a distribution is ______.
Consider the following frequency distribution:
| Class | 0 – 6 | 6 – 12 | 12 – 18 | 18 – 24 | 24 – 30 |
| Frequency | 12 | 10 | 15 | 8 | 11 |
The median class is:
A survey conducted on 20 households in a locality by a group of students resulted in the following frequency table for the number of family members in a household:
| Family size | 1 – 3 | 3 – 5 | 5 – 7 | 7 – 9 | 9 – 11 |
| Numbers of Families | 7 | 8 | 2 | 2 | 1 |
Find the median of this data.
The following table shows classification of number of workers and number of hours they work in software company. Prepare less than upper limit type cumulative frequency distribution table:
| Number of hours daily | Number of workers |
| 8 - 10 | 150 |
| 10 - 12 | 500 |
| 12 - 14 | 300 |
| 14 - 16 | 50 |
