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प्रश्न
The following table shows classification of number of workers and number of hours they work in software company. Prepare less than upper limit type cumulative frequency distribution table:
| Number of hours daily | Number of workers |
| 8 - 10 | 150 |
| 10 - 12 | 500 |
| 12 - 14 | 300 |
| 14 - 16 | 50 |
उत्तर
| Number of hours daily | Number of workers | Cumulative Frequency |
| 8 - 10 | 150 | 150 |
| 10 - 12 | 500 | 150 + 500 = 650 |
| 12 - 14 | 300 | 650 + 300 = 950 |
| 14 - 16 | 50 | 950 + 50 = 1000 |
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संबंधित प्रश्न
An incomplete distribution is given below:
| Variable: | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | 60-70 | 70-80 |
| Frequency: | 12 | 30 | - | 65 | - | 25 | 18 |
You are given that the median value is 46 and the total number of items is 230.
(i) Using the median formula fill up missing frequencies.
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The weights (in kg) of 10 students of a class are given below:
21, 28.5, 20.5, 24, 25.5, 22, 27.5, 28, 21 and 24.
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| Age- group (Yrs.) | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | 60-70 |
| No. of patients | 40 | 32 | 35 | 45 | 33 | 15 |
Which measure of central tendency can be determine graphically?
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66, 98, 54, 92, 87, 63, 72.
The Median when it is given that mode and mean are 8 and 9 respectively, is ______.
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| Class | 0 – 5 | 6 – 11 | 12 – 17 | 18 – 23 | 24 – 29 |
| Frequency | 13 | 10 | 15 | 8 | 11 |
The upper limit of the median class is:
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| Monthly Consumption (in units) |
130 – 140 | 140 – 150 | 150 – 160 | 160 – 170 | 170 – 180 | 180 – 190 | 190 – 200 |
| Number of families |
5 | 9 | 17 | 28 | 24 | 10 | 7 |
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