Advertisements
Advertisements
प्रश्न
The following table shows the number of patients of different age groups admitted to a hospital for treatment on a day. Find the median of ages of the patients.
Age- group (Yrs.) | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | 60-70 |
No. of patients | 40 | 32 | 35 | 45 | 33 | 15 |
उत्तर
Age (Yrs.) | No. of patients (Frequency) |
Cumulative frequency (Less than) |
10-20 | 40 | 40 |
20-30 | 32 | 72 |
30-40 | 35 | 107 |
40-50 | 45 | 152 |
50-60 | 33 | 185 |
60-70 | 15 | 200 |
Here N = 200 ∴ the number` N/2=`100 which is included in the class 30-40
∴ median class is 30 - 40
∴ L = 30, cf = 72, f = 35, h = 10
Median = L+ `|(n/2-cf)/f| xx h`
`=30+((100-72)/35) xx 10`
`=30+(28xx2)/7`
= 30 + 4 x 2
= 30 + 8 = 38
∴ median of ages of patients is 38.
APPEARS IN
संबंधित प्रश्न
100 surnames were randomly picked up from a local telephone directory and the frequency distribution of the number of letters in the English alphabets in the surnames was obtained as follows:
Number of letters | Number of surnames |
1 - 4 | 6 |
4 − 7 | 30 |
7 - 10 | 40 |
10 - 13 | 6 |
13 - 16 | 4 |
16 − 19 | 4 |
Determine the median number of letters in the surnames. Find the mean number of letters in the surnames? Also, find the modal size of the surnames.
If the median of the distribution given below is 28.5, find the values of x and y.
Class interval | Frequency |
0 - 10 | 5 |
10 - 20 | x |
20 - 30 | 20 |
30 - 40 | 15 |
40 - 50 | y |
50 - 60 | 5 |
Total | 60 |
For a certain frequency distribution, the values of Assumed mean (A) = 1300, `sumf_id_i` = 900 and `sumfi` = 100. Find the value of mean (`barx`) .
For a certain frequency distribution, the values of mean and median are 72 and 78 respectively. Find the value of mode.
The table below shows the salaries of 280 persons :
Salary (In thousand Rs) | No. of Persons |
5 – 10 | 49 |
10 – 15 | 133 |
15 – 20 | 63 |
20 – 25 | 15 |
25 – 30 | 6 |
30 – 35 | 7 |
35 – 40 | 4 |
40 – 45 | 2 |
45 – 50 | 1 |
Calculate the median salary of the data.
The following is the distribution of height of students of a certain class in a certain city:
Height (in cm): | 160 - 162 | 163 - 165 | 166 - 168 | 169 - 171 | 172 - 174 |
No. of students: | 15 | 118 | 142 | 127 | 18 |
Find the median height.
The following table gives the frequency distribution of married women by age at marriage:
Age (in years) | Frequency |
15-19 | 53 |
20-24 | 140 |
25-29 | 98 |
30-34 | 32 |
35-39 | 12 |
40-44 | 9 |
45-49 | 5 |
50-54 | 3 |
55-59 | 3 |
60 and above | 2 |
Calculate the median and interpret the results.
A survey regarding the height (in cm) of 51 girls of class X of a school was conducted and the following data was obtained:
Height in cm | Number of Girls |
Less than 140 | 4 |
Less than 145 | 11 |
Less than 150 | 29 |
Less than 155 | 40 |
Less than 160 | 46 |
Less than 165 | 51 |
Find the median height.
From the following data, find:
Inter-quartile range
25, 10, 40, 88, 45, 60, 77, 36, 18, 95, 56, 65, 7, 0, 38 and 83
Calculate the median from the following frequency distribution table:
Class | 5 – 10 | 10 – 15 | 15 – 20 | 20 – 25 | 25 – 30 | 30 – 35 | 35 – 40 | 40 – 45 |
Frequency | 5 | 6 | 15 | 10 | 5 | 4 | 2 | 2 |
The arithmetic mean and mode of a data are 24 and 12 respectively, then its median is
If 35 is removed from the data: 30, 34, 35, 36, 37, 38, 39, 40, then the median increased by
Find the Median of the following distribution:
x | 3 | 5 | 10 | 12 | 8 | 15 |
f | 2 | 4 | 6 | 10 | 8 | 7 |
Find the median of the following frequency distribution:
x | 10 | 11 | 12 | 13 | 14 | 15 |
f | 1 | 4 | 7 | 5 | 9 | 3 |
Calculate the median of the following distribution:
Weight (in nearest kg.) | No. of students |
46 | 7 |
48 | 5 |
50 | 8 |
52 | 12 |
53 | 10 |
54 | 2 |
55 | 1 |
Calculate the median of the following distribution:
No. of goals | 0 | 1 | 2 | 3 | 4 | 5 |
No. of matches | 2 | 4 | 7 | 6 | 8 | 3 |
The maximum bowling speeds, in km per hour, of 33 players at a cricket coaching centre are given as follows:
Speed (km/h) | 85 – 100 | 100 – 115 | 115 – 130 | 130 – 145 |
Number of players | 11 | 9 | 8 | 5 |
Calculate the median bowling speed.
Following is the distribution of the long jump competition in which 250 students participated. Find the median distance jumped by the students. Interpret the median
Distance (in m) |
0 – 1 | 1 – 2 | 2 – 3 | 3 – 4 | 4 – 5 |
Number of Students |
40 | 80 | 62 | 38 | 30 |
Using the empirical relationship between the three measures of central tendency, find the median of a distribution, whose mean is 169 and mode is 175.