हिंदी

A Survey Regarding the Height (In Cm) of 51 Girls of Class X of a School Was Conducted and the Following Data Was Obtained: - Mathematics

Advertisements
Advertisements

प्रश्न

A survey regarding the height (in cm) of 51 girls of class X of a school was conducted and the following data was obtained:

Height in cm Number of Girls
Less than 140 4
Less than 145 11
Less than 150 29
Less than 155 40
Less than 160 46
Less than 165 51

Find the median height.

उत्तर

To calculate the median height, we need to find the class intervals and their corresponding frequencies

The given distribution being of thee less than type 140, 145, 150,…..,165 give the upper limits of the corresponding class intervals. So, the classes should be below 140, 145, 150,......, 160, 165 observe that from the given distribution, we find that there are 4-girls with height less than 140 is 4. Now there are 4 girls with heights less than 140. Therefore, the number of girls with height in the interval 140, 145 is 11- 4=7, similarly. The frequencies of 145 150 is 29-11=18, for 150-155 it is 40-29=11, and so on so our
frequencies distribution becomes.

Class interval Frequency Cumulative frequency
below 140 4 4
140-145 7 11
145-150 18 29
150-155 11 40
155-160 6 46
160-165 5 51

Now N = 51

So, N/2=51/2=25.5

Now, the cumulative frequency just greater than 25.5 is 29 and the corresponding class is 145 - 150.

Therefore, 145 - 150 is the median class.

l = 145, f = 18, F = 11 and h = 5

We know that

Median `=l+(N/2-F)/fxxh`

`=145+(25.5-11)/18xx5`

`=145+14.5/18xx5`

`=145+72.5/18`

= 145 + 4.03

= 149.03

Hence, the median height is 149.03

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 15: Statistics - Exercise 15.4 [पृष्ठ ३६]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 10
अध्याय 15 Statistics
Exercise 15.4 | Q 16 | पृष्ठ ३६

वीडियो ट्यूटोरियलVIEW ALL [4]

संबंधित प्रश्न

The following is the distribution of the size of certain farms from a taluka (tehasil):

Size of Farms
(in acres)
Number of Farms
5 – 15 7
15 – 25 12
25 – 35 17
35 – 45 25
45 – 55 31
55 – 65 5
65 – 75 3

Find median size of farms.


The marks obtained by 30 students in a class assignment of 5 marks are given below.

Marks 0 1 2 3 4 5
No. of
Students
1 3 6 10 5 5

Calculate the mean, median and mode of the above distribution


The following is the distribution of height of students of a certain class in a certain city:

Height (in cm): 160 - 162 163 - 165 166 - 168 169 - 171 172 - 174
No. of students: 15 118 142 127 18

Find the median height.


Calculate the median from the following data:

Rent (in Rs.): 15 - 25 25 - 35 35 - 45 45 - 55 55 - 65 65 - 75 75 - 85 85 - 95
No. of Houses: 8 10 15 25 40 20 15 7

From the following data, find: 

Inter-quartile range

25, 10, 40, 88, 45, 60, 77, 36, 18, 95, 56, 65, 7, 0, 38 and 83


In the graphical representation of a frequency distribution, if the distance between mode and mean is ktimes the distance between median and mean, then write the value of k.


If the median of the data: 24, 25, 26, x + 2, x + 3, 30, 31, 34 is 27.5, then x =


If the median of the data: 6, 7, x − 2, x, 17, 20, written in ascending order, is 16. Then x=


Find the values of a and b, if the sum of all the frequencies is 120 and the median of the following data is 55.

Marks 30 – 40 40 – 50 50 –60 60 – 70 70 –80 80 – 90
Frequency a 40 27 b 15 24

Heights of 50 students of class X of a school are recorded and following data is obtained:

Height (in cm) 130 – 135 135 – 140 140 – 145 145 – 150 150 – 155 155 – 160
Number of students 4 11 12 7 10 6

Find the median height of the students.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×