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प्रश्न
Calculate the median from the following data:
Rent (in Rs.): | 15 - 25 | 25 - 35 | 35 - 45 | 45 - 55 | 55 - 65 | 65 - 75 | 75 - 85 | 85 - 95 |
No. of Houses: | 8 | 10 | 15 | 25 | 40 | 20 | 15 | 7 |
उत्तर
Class interval | Frequency | Cumulative frequency |
15 - 25 | 8 | 8 |
25 - 35 | 10 | 18 |
35 - 45 | 15 | 33 |
45 - 55 | 25 | 58 |
55 - 65 | 40 | 98 |
65 - 75 | 20 | 118 |
75 - 85 | 15 | 133 |
85 - 95 | 7 | 140 |
N = 140 |
Here N = 140
So, N/2 = 70
Thus, the cumulative frequency just greater than 70 is 98 and the corresponding class is 55 - 65.
Therefore, 55 - 65 is the median class.
Here, l = 55, f = 40, F = 58 and h = 10
We know that
Median `=l +{(N/2-F)/f}xxh`
`=55+{(70-58)/40}xx10`
`=55+(12xx10)/40`
`=55+120/40`
= 55 + 3
= 58
Hence, the median is 58.
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संबंधित प्रश्न
From the following data, find:
Upper quartile
25, 10, 40, 88, 45, 60, 77, 36, 18, 95, 56, 65, 7, 0, 38 and 83
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Class | 0 – 10 | 10 – 20 | 20 – 30 | 30 -40 | 40 – 50 | 50 – 60 | 60 – 70 | Total |
Frequency | `f_1` |
5 |
9 | 12 | `f_2` | 3 | 2 | 40 |
Find the median from the following data:
Marks | No of students |
Below 10 | 12 |
Below 20 | 32 |
Below 30 | 57 |
Below 40 | 80 |
Below 50 | 92 |
Below 60 | 116 |
Below 70 | 164 |
Below 80 | 200 |
If the difference of Mode and Median of a data is 24, then the difference of median and mean is ______.
Find the median of:
66, 98, 54, 92, 87, 63, 72.
The Median when it is given that mode and mean are 8 and 9 respectively, is ______.
The median of the following data is 525. Find the values of x and y, if the total frequency is 100.
Class interval | Frequency |
0 – 100 | 2 |
100 – 200 | 5 |
200 – 300 | x |
300 – 400 | 12 |
400 – 500 | 17 |
500 – 600 | 20 |
600 – 700 | y |
700 – 800 | 9 |
800 – 900 | 7 |
900 – 1000 | 4 |
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Class: | 0 – 10 | 10 – 20 | 20 – 30 | 30 – 40 | 40 – 50 |
Frequency: | 6 | 3 | x | 12 | 19 |
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Class: | 0 – 20 | 20 – 40 | 40 – 60 | 60 – 80 | 80 – 100 |
Frequency: | 6 | 8 | 5 | 9 | 7 |
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