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प्रश्न
Find the median of the following frequency distribution:
| Class: | 0 – 20 | 20 – 40 | 40 – 60 | 60 – 80 | 80 – 100 |
| Frequency: | 6 | 8 | 5 | 9 | 7 |
उत्तर
| Class Interval | Frequency | Cumulative frequency (cf) |
| 0 – 20 | 6 | 6 |
| 20 – 40 | 8 | 14 |
| 40 – 60 | 5 | 19 |
| 60 – 80 | 9 | 28 |
| 80 – 100 | 7 | 35 |
| N = `sumf_i` = 35 |
Here, N = 35
⇒ `"N"/2 = 35/2`
So, Median class is 40 – 60
Lower limit of median class (l) = 40
Class width (h) = 20
Frequency of median class (f) = 5
Precceding cf of median class (`"C"_f`) = 14
∴ Median = `l + ((N/2 - "C"_f)/f) xx h`
= `40 + ((35/2 - 14)/5) xx 20`
= 40 + 7 × 2
= 54
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संबंधित प्रश्न
Below is the given frequency distribution of words in an essay
| Number of Words | Number of Candidates |
| 600 – 800 | 8 |
| 800 – 1000 | 22 |
| 1000 – 1200 | 40 |
| 1200 – 1400 | 18 |
| 1400 - 1600 | 12 |
Find the mean number of words written.
For a certain frequency distribution, the values of Assumed mean (A) = 1300, `sumf_id_i` = 900 and `sumfi` = 100. Find the value of mean (`barx`) .
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| Frequency | 6 | 10 | 18 | 22 | 20 | 15 | 6 | 3 |
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| No. of cars | 11 | 12 | 20 | 7 |
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The median of the following data is 50. Find the values of p and q, if the sum of all the frequencies is 90.
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| Frequency: | P | 15 | 25 | 20 | q | 8 | 10 |
Find the values of a and b, if the sum of all the frequencies is 120 and the median of the following data is 55.
| Marks | 30 – 40 | 40 – 50 | 50 –60 | 60 – 70 | 70 –80 | 80 – 90 |
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The median of the following frequency distribution is 35. Find the value of x.
| Class: | 0 – 10 | 10 – 20 | 20 – 30 | 30 – 40 | 40 – 50 |
| Frequency: | 6 | 3 | x | 12 | 19 |
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| Monthly Expenditure (in ₹) |
1000 – 1500 | 1500 – 2000 | 2000 – 2500 | 2500 – 3000 | 3000 – 3500 | 3500 – 4000 | 4000 – 4500 | 4500 – 5000 |
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