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प्रश्न
The following table gives the monthly consumption of electricity of 100 families:
| Monthly Consumption (in units) |
130 – 140 | 140 – 150 | 150 – 160 | 160 – 170 | 170 – 180 | 180 – 190 | 190 – 200 |
| Number of families |
5 | 9 | 17 | 28 | 24 | 10 | 7 |
Find the median of the above data.
उत्तर
From the given table,
| Monthly Consumption |
Number of Families (f) |
Cumulative frequency (C.f.) |
| 130 – 140 | 5 | 5 |
| 140 – 150 | 9 | 14 |
| 150 – 160 | 17 | 31 |
| 160 – 170 | 28 | 59 |
| 170 – 180 | 24 | 83 |
| 180 – 190 | 10 | 93 |
| 190 – 200 | 7 | 100 |
We have, N = 100
`N/2` = 50
Median class = 160 – 170
`\implies` l = 160, f = 28, Cf = 31, h = 10
Median = `l + [((N/2 - Cf))/f] xx h`
= `160 + [((50 - 31))/28] xx 10`
= `160 + [19/28] xx 10`
= 160 + 6.78
= 166.78
संबंधित प्रश्न
Following are the lives in hours of 15 pieces of the components of aircraft engine. Find the median:
715, 724, 725, 710, 729, 745, 694, 699, 696, 712, 734, 728, 716, 705, 719.
Following is the distribution of I.Q. of loo students. Find the median I.Q.
| I.Q.: | 55 - 64 | 65 - 74 | 75 - 84 | 85 - 94 | 95 - 104 | 105 - 114 | 115 - 124 | 125 - 134 | 135 - 144 |
| No of Students: | 1 | 2 | 9 | 22 | 33 | 22 | 8 | 2 | 1 |
Find the missing frequencies and the median for the following distribution if the mean is 1.46.
| No. of accidents: | 0 | 1 | 2 | 3 | 4 | 5 | Total |
| Frequency (No. of days): | 46 | ? | ? | 25 | 10 | 5 | 200 |
Calculate the median from the following data:
| Height(in cm) | 135 - 140 | 140 - 145 | 145 - 150 | 150 - 155 | 155 - 160 | 160 - 165 | 165 - 170 | 170 - 175 |
| Frequency | 6 | 10 | 18 | 22 | 20 | 15 | 6 | 3 |
Find the median from the following data:
| Marks | No of students |
| Below 10 | 12 |
| Below 20 | 32 |
| Below 30 | 57 |
| Below 40 | 80 |
| Below 50 | 92 |
| Below 60 | 116 |
| Below 70 | 164 |
| Below 80 | 200 |
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| Class: | 0 – 20 | 20 – 40 | 40 – 60 | 60 – 80 | 80 – 100 |
| Frequency: | 6 | 8 | 5 | 9 | 7 |
