Question

By how much does 3x² − 5x + 6 exceed x³ − x² + 4x − 1?

Answer 1

To calculate how much does 3x² − 5x + 6 exceed x³ − x² + 4x − 1, we have to subtract x³ − x² + 4x − 1 from 3x² − 5x + 6.
Change the sign of each term of the expression that is to be subtracted and then add.

 Term to be subtracted = x³ − x² + 4x − 1
Changing the sign of each term of the expression gives -x³ + x² - 4x + 1.
On adding:
(3x² − 5x + 6)+(-x³ + x² - 4x + 1 )
= 3x² − 5x + 6-x³ + x² - 4x + 1
= -x³ + (3+1)x² +(-5-4)x+6 + 1
 = -x³ +4 x² - 9x + 7