Advertisements
Advertisements
प्रश्न
By how much does 3x2 − 5x + 6 exceed x3 − x2 + 4x − 1?
उत्तर
To calculate how much does 3x2 − 5x + 6 exceed x3 − x2 + 4x − 1, we have to subtract x3 − x2 + 4x − 1 from 3x2 − 5x + 6.
Change the sign of each term of the expression that is to be subtracted and then add.
Term to be subtracted = x3 − x2 + 4x − 1
Changing the sign of each term of the expression gives -x3 + x2 - 4x + 1.
On adding:
(3x2 − 5x + 6)+(-x3 + x2 - 4x + 1 )
= 3x2 − 5x + 6-x3 + x2 - 4x + 1
= -x3 + (3+1)x2 +(-5-4)x+6 + 1
= -x3 +4 x2 - 9x + 7
APPEARS IN
संबंधित प्रश्न
Write the constant term of 3x2 + 5x + 8
Identify the monomials, binomials, and trinomials in the following:
2x + 1
Identify the like terms in the following:
abc, ab2c, acb2, c2ab, b2ac, a2bc, cab2
Add
8a − 6ab + 5b, −6a − ab − 8b, −4a + 2ab + 3b
Annual salary at r rupees per month alongwith a festival bonus of Rs 2000 is ______.
The successor of an integer.
The number of students dropping out of school last year was m. Number of students dropping out of school this year is m – 30.
Give expression for the following case.
7 added to p
Give expression for the following case.
− p multiplied by 5
Give expression in the following case.
11 added to 2m
