Question

Calculate Standard cell potential for a cell having following reaction, \[\ce{2Al(s) + 3Ni^{2+} -> 2Al^{3+} + 3Ni(s)}\]

`("E"_"Ni"^circ = - 0.25 "V" and "E"_"Al"^circ = 1.66 "V")`

विकल्प

• - 0.50 V

• 0.41 V

• 1.41 V

• 0.50 V

Answer 1

1.41 V

Explanation:

Given, `"E"_"Ni"^circ` = - 0.25 V

`"E"_"Al"^circ` = - 1.66 V

`"E"_"cell"^circ = "E"_"cathode"^circ - "E"_"anode"^circ`

= - 0.25 - (- 1.66)

= 1.41 V