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प्रश्न
Calculate the minimum amount of energy which a gamma ray photon should have for the production of an electron and a positron pair..
उत्तर
The equation representing pair production is given by,
hv = -1β0 + 1β0
This equation follows Einstein's- mass energy relation. So, for this process to occur, energy of photon should be at least equal to the rest mass energy of electron and position.
Therefore hv = 2moc2 ...(Here mo is the rest mass energy of electron)
`= 2 xx 9.1 xx 10^-31 "kg" xx (3 xx 10^8)^2 ("ms"^-1)^2`
`= 2 xx 8.2 xx 106-14`J
`= (16.4 xx 10^-14)/(1.6 xx 10^-19 "J"//"eV")`
= 1.02 × 106 eV
= 1.02 MeV
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