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प्रश्न
Calculate the total number of electrons flowing through a circuit in 20 mins and 40 s, if a current of 40 μA flows through the circuit.
[1 e– = 1.6 × 10-19 C]
उत्तर
Number of electrons = n = ?
Time = t = 20 min 40 s
t = (20 × 60 + 40) s
t = 1240 s
Electric current = I = 40 μA
I = 40 × 10-6 A
Charge on one electron = 1 e = 1.6 × 10-19 C
Charge = Q = ?
I = `"Q"/"t"`
Q = It
Q = 40 × 10-6 × 1240
Q = 49600 × 10-6 C
Q = 4.96 × 10-2 C
Now Q = n (charge on 1 electron) = ne
4.96 × 10-2 = n × 1.6 × 10-19
n = `(4.96 xx 10^-2)/(1.6xx10^-19)`
n = 3.1 × 1017 electrons
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