Advertisements
Advertisements
प्रश्न
4 × 1020 electrons flow through a circuit in 10 hours. Calculate magnitude of current. [1 e- = 1.6 × 10-19 C]
उत्तर
Number of electrons = n = 4 × 1020
Time = t = 10 hours
t = 10 × 60 × 60 s
t = 36000 s
Charge on one electron = e = 1.6 × 10-19 C
Electric current = I = ?
Charge = Q = ne
Q = 4 × 1020 × 1.6 × 10-19
Q = 6.4 × 101
Q = 64 C
Electric current = I = `"Q"/"t"`
I = `64/36000 = 64/36 xx 10^-3"A"`
`= 16/9 xx 10^-3`
I = 1.77 × 10-3A
I = 1.77 mA
APPEARS IN
संबंधित प्रश्न
When starter motor of a car is switched on for 0.8 s . a charge 24 C passes through the coil of the motor . Calculate the current in the coil .
Explain the concept of electric potential difference in terms of work done in transferring the charge.
State three factors on which the resistance of a wire depends. Explain how the resistance depends on the factors stated by you.
Current in a circuit flows :
State SI unit of electric charge and define it.
A charge of 8860 C flows through an electric circuit in 2 min and 40 s. Calculate the magnitude of current in a circuit.
State the kind of charge on a positive ion.
A bulb is connected to a cell. How is the resistance of circuit affected if another identical bulb is connected (i) in series, (ii) in parallel, with the first bulb?
