Advertisements
Advertisements
प्रश्न
Car A travels x km for every litre of petrol, while car B travels (x + 5) km for every litre of petrol.
Write down the number of litres of petrol used by car A and car B in covering a distance of 400 km.
उत्तर
Given Distance = 400 km
Car A travels x km/litre.
Car B travels (x + 5) km/litre.
No, of litre used by car
A = `"Distance"/"Speed of car A"`
= `(400)/x"litre"`.
No. of litre used by car B = `"Distance"/"Speed of car B"`
= `(400)/(x + 5)"liter"`.
APPEARS IN
संबंधित प्रश्न
The numerator of a fraction is 3 less than its denominator. If 2 is added to both the numerator and the denominator, then the sum of the new fraction and original fraction is `29/20`. Find the original fraction.
Solve the following quadratic equations by factorization:
a(x2 + 1) - x(a2 + 1) = 0
A passenger train takes 2 hours less for a journey of 300 km if its speed is increased by 5 km/hr from its usual speed. Find the usual speed of the train.
A takes 10 days less than the time taken by B to finish a piece of work. If both A and B together can finish the work in 12 days, find the time taken by B to finish the work.
Out of a group of swans, 7/2 times the square root of the total number are playing on the share of a pond. The two remaining ones are swinging in water. Find the total number of swans.
If the sum of the roots of the equation \[x^2 - \left( k + 6 \right)x + 2\left( 2k - 1 \right) = 0\] is equal to half of their product, then k =
Solve the following quadratic equation by factorisation:
(x - 4) (x + 2) = 0
The lengths of the parallel sides of a trapezium are (x + 9) cm and (2x – 3) cm and the distance between them is (x + 4) cm. If its area is 540 cm2, find x.
Solve the following equation by factorisation :
`sqrt(3x^2 - 2x - 1) = 2x - 2`
Solve the quadratic equation by factorisation method:
x2 – 15x + 54 = 0
