Advertisements
Advertisements
प्रश्न
Check whether the following is quadratic equation or not.
`(x+1/x)^2=3(1+1/x)+4`
उत्तर
Here it has been given that,
`(x+1/x)^2=3(1+1/x)+4`
Now, solving the above equation further we get,
`((x^2+1)/x)^2=(3x^2+1+4x)/x`
Now as we can see, the above equation clearly does not represent a quadratic equation of the form ax2 + bx + c = 0, because x4 - 3x3 - 2x2 - x + 1 is a polynomial having a degree of 4 which is never present in a quadratic polynomial.
Hence, the above equation is not a quadratic equation.
APPEARS IN
संबंधित प्रश्न
Sum of two natural numbers is 8 and the difference of their reciprocal is `2/15`. Find the numbers.
Solve `6/x = 1 + x`
(x + 3)² – 4(x + 3) – 5 = 0
Solve:
(x2 – x)2 + 5(x2 – x) + 4 = 0
Which of the following are quadratic equation in x?
`1/3x^2+1/5x-2=0`
Which of the following are quadratic equation in x?
`x^2-3x-sqrtx+4=0`
`sqrt3x^2+10x7sqrt3=0`
`(x-4)/(x-5)+(x-6)/(x-7)=31/3,x≠5,7`
Find the value of x, if a + 7 = 0; b + 10 = 0 and 12x2 = ax – b.
If x2 – 8x – 9 = 0; values of x correct to one significant figure are ______.