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Check whether the following is quadratic equation or not.
(2ЁЭСе + 1)(3ЁЭСе + 2) = 6(ЁЭСе − 1)(ЁЭСе − 2)
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Here it has been given that,
(2ЁЭСе + 1)(3ЁЭСе + 2) = 6(ЁЭСе − 1)(ЁЭСе − 2)
Now, after solving the above equation further we get,
6x2 + 7x + 2 = 6x2 - 18x + 12
25x - 10 = 0
5x - 2 = 0
Now as we can see, the above equation clearly does not represent a quadratic equation of the form ax2 + bx + c = 0, because 5x - 2 = 0 is a linear equation.
Hence, the above equation is not a quadratic equation.
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