हिंदी
तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएचएससी विज्ञान कक्षा ११

Choose the correct alternative:The solution of 5x − 1 < 24 and 5x + 1 > −24 is - Mathematics

Advertisements
Advertisements

प्रश्न

Choose the correct alternative:
The solution of 5x − 1 < 24 and 5x + 1 > −24 is

विकल्प

  • (4, 5)

  • (−5, −4)

  • (−5, 5)

  • (−5, 4)

MCQ

उत्तर

(−5, 5)

shaalaa.com
Rational Functions
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Basic Algebra - Exercise 2.13 [पृष्ठ ८१]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 2 Basic Algebra
Exercise 2.13 | Q 4 | पृष्ठ ८१

संबंधित प्रश्न

Find all values of x that satisfies the inequality `(2x - 3)/((x - 2)(x - 4)) < 0`


Resolve the following rational expressions into partial fractions

`1/(x^2 - "a"^2)`


Resolve the following rational expressions into partial fractions

`(3x + 1)/((x - 2)(x + 1))`


Resolve the following rational expressions into partial fractions

`x/((x^2 + 1)(x - 1)(x + 2))`


Resolve the following rational expressions into partial fractions

`1/(x^4 - 1)`


Resolve the following rational expressions into partial fractions

`(x^2 + x + 1)/(x^2 - 5x + 6)`


Resolve the following rational expressions into partial fractions

`(x^3 + 2x + 1)/(x^2 + 5x + 6)`


Resolve the following rational expressions into partial fractions

`(x + 12)/((x + 1)^2 (x - 2))`


Resolve the following rational expressions into partial fractions

`(6x^2 - x + 1)/(x^3 + x^2 + x + 1)`


Resolve the following rational expressions into partial fractions

`(2x^2 + 5x - 11)/(x^2 + 2x - 3)`


Resolve the following rational expressions into partial fractions

`(7 + x)/((1 + x)(1 + x^2))`


Determine the region in the plane determined by the inequalities:

x ≤ 3y, x ≥ y


Determine the region in the plane determined by the inequalities:

3x + 5y ≥ 45, x ≥ 0, y ≥ 0


Determine the region in the plane determined by the inequalities:

2x + 3y ≤ 35, y ≥ 2, x ≥ 5.


Determine the region in the plane determined by the inequalities:

x − 2y ≥ 0, 2x − y ≤ −2, x ≥ 0, y ≥ 0


Choose the correct alternative:
The solution set of the following inequality |x − 1| ≥ |x − 3| is


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×