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प्रश्न
Complete the following table.
उत्तर
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संबंधित प्रश्न
Solve the problem.
How much time a satellite in an orbit at height 35780 km above earth's surface would take, if the mass of the earth would have been four times its original mass?
If the height of a satellite completing one revolution around the earth in T seconds is h1 meter, then what would be the height of a satellite taking \[2\sqrt{2} T\] seconds for one revolution?
Considering first correlation, complete the second.
Hubble telescope : At 569 km above the earth’s surface
Orbit of Hubble telescope : .............................
Mahendra and Virat are sitting at a distance of 1 metre from each other. Their masses are 75 kg and 80 kg respectively. What is the gravitational force between them? G = 6.67 x 10-11 Nm2/kg2
Name the first artificial satellite sent by Russia in space.
Calculate the critical velocity of the satellite to be located at 35780 km above the surface of earth.
Write functions of Military satellite and Navigational satellite.
How is a satellite maintained in nearly circular orbit?
Numerical problem.
Calculate the speed with which a satellite moves if it is at a height of 36,000 km from the Earth’s surface and has an orbital period of 24 hr (Take R = 6370 km) [Hint: Convert hr into seconds before doing calculation]
Numerical problem.
At an orbital height of 400 km, find the orbital period of the satellite.
What is microgravity?
The orbital velocity of the satellite depends on its ______.
Write down the formula of orbital velocity.
Geostationary satellites are not useful for studies of the polar region.
Calculate the time taken by a satellite for one revolution revolving at a height of 6400 km above the earth's surface with a velocity of 5.6 km/s.
Complete the Following table.
| Sr. no. | Type of Satellite | The names of Indian Satellite and launcher |
| (1) | Navigational Satellite | Satellite: ______ |
| Launcher: ______ | ||
| (2) | Earth Observation Satellite | Satellite: ______ |
| Launcher: ______ |
Complete the following equations:
The orbit of a satellite is exactly 35780 km above the earth's surface and its tangential velocity is 3.08 km/s.
How much time the satellite will take to complete one revolution around the earth?
(Radius of earth = 6400 km.)
