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Question
Complete the following table.
Solution
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Fill in the blank and explain the statement with reasoning:
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Column-1 (Location) |
Column-2 Height from the earth’s surface (km) |
Column-3 g (m/s2) |
Earth’s surface (average) | 8.8 | 0.225 |
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Orbit of communication satellite | 0 | 8.7 |
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Numerical problem.
Calculate the speed with which a satellite moves if it is at a height of 36,000 km from the Earth’s surface and has an orbital period of 24 hr (Take R = 6370 km) [Hint: Convert hr into seconds before doing calculation]
The height of medium earth orbit above the surface of the earth is ______.
Complete the following equations:
The orbit of a satellite is exactly 35780 km above the earth's surface and its tangential velocity is 3.08 km/s.
How much time the satellite will take to complete one revolution around the earth?
(Radius of earth = 6400 km.)