Question

Complete the following nuclear fission reaction:

$${\phantom{A}}_{\phantom{92}}^{\phantom{235}}{\phantom{A}}_{\phantom{2}92}^{\phantom{2}235}\mathrm{U}+{\phantom{A}}_{\phantom{0}}^{\phantom{1}}{\phantom{A}}_{\phantom{2}0}^{\phantom{2}1}\mathrm{n}⟶{\phantom{A}}_{\phantom{56}}^{\phantom{}}{\phantom{A}}_{\phantom{2}56}^{\phantom{2}}\mathrm{Ba}+{\phantom{A}}_{\phantom{}}^{\phantom{92}}{\phantom{A}}_{\phantom{2}}^{\phantom{2}92}\mathrm{Kr}+3{\phantom{A}}_0{\phantom{A}}^1\mathrm{n}+$$______.

Answer 1

$${\phantom{A}}_{\phantom{92}}^{\phantom{235}}{\phantom{A}}_{\phantom{2}92}^{\phantom{2}235}\mathrm{U}+{\phantom{A}}_{\phantom{0}}^{\phantom{1}}{\phantom{A}}_{\phantom{2}0}^{\phantom{2}1}\mathrm{n}⟶{\phantom{A}}_{\phantom{56}}^{\phantom{141}}{\phantom{A}}_{\phantom{2}56}^{\phantom{2}141}\mathrm{Ba}+{\phantom{A}}_{\phantom{16}}^{\phantom{92}}{\phantom{A}}_{\phantom{2}16}^{\phantom{2}92}\mathrm{Kr}+3{\phantom{A}}_{\phantom{0}}^{\phantom{1}}{\phantom{A}}_{\phantom{2}0}^{\phantom{2}1}\mathrm{n}+\underset{―}{\text{Energy}}$$.