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प्रश्न
Concentrated sulphuric acid is both an oxidizing agent and a non-volatile acid. Write one equation. Each illustrates the above-mentioned properties of sulphuric acid.
उत्तर
- Oxidising agent: Concentrated sulphuric acid as an oxidising agent and oxidises carbon to carbon dioxide.
\[\ce{\underset{Carbon}{C} + 2H2HO4 -> \underset{carbo dioxide}{CO2} + 2SO2 + 2H2O}\] - Non-volatile acid: Concentrated sulphuric acid has a high boiling point (338°C) that is why it is said to be a non-volatile compound, therefore, it is used for preparing volatile acids like hydrochloric acids and nitric acids from there salt by double decomposition
\[\ce{H2SO4 + NaCl -> NaHSO4 + HCl}\]
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संबंधित प्रश्न
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