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Concentrated sulphuric acid is both an oxidizing agent and a non-volatile acid. Write one equation. Each illustrates the above-mentioned properties of sulphuric acid. - Chemistry

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Question

Concentrated sulphuric acid is both an oxidizing agent and a non-volatile acid. Write one equation. Each illustrates the above-mentioned properties of sulphuric acid.

Chemical Equations/Structures
Short Answer

Solution

  1. Oxidising agent: Concentrated sulphuric acid as an oxidising agent and oxidises carbon to carbon dioxide.
    \[\ce{\underset{Carbon}{C} + 2H2HO4 -> \underset{carbo dioxide}{CO2} + 2SO2 + 2H2O}\]
  2. Non-volatile acid: Concentrated sulphuric acid has a high boiling point (338°C) that is why it is said to be a non-volatile compound, therefore, it is used for preparing volatile acids like hydrochloric acids and nitric acids from there salt by double decomposition
    \[\ce{H2SO4 + NaCl -> NaHSO4 + HCl}\]
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Sulphuric Acid
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Chapter 11: Sulphuric Acid - Exercise 11 [Page 180]

APPEARS IN

Selina Concise Chemistry [English] Class 10 ICSE
Chapter 11 Sulphuric Acid
Exercise 11 | Q 11.2 | Page 180

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