Question

Consider structures I to VII and answer the question:

I.	CH3 – CH2 – CH2 – CH2 – OH
II.	\[\begin{array}{cc} \ce{CH3 - CH2 - CH - CH3}\\ \phantom{.....}|\\ \phantom{.......}\ce{OH} \end{array}\]
III.	\[\begin{array}{cc} \phantom{...}\ce{CH3}\\ \phantom{}|\\ \ce{CH3 - C - CH3}\\ \phantom{}|\\ \phantom{..}\ce{OH} \end{array}\]
IV.	\[\begin{array}{cc} \ce{CH3 - CH - CH2 - OH}\\ |\phantom{........}\\ \ce{CH3}\phantom{......} \end{array}\]
V.	CH3 – CH2 – O – CH2 – CH3
VI.	CH3 – O – CH2 – CH2 – CH3
VII.	\[\begin{array}{cc} \ce{CH3 - O - CH - CH3}\\ \phantom{...}|\\ \phantom{......}\ce{CH3} \end{array}\]

Which of the above compounds form pairs of metamers?

Answer 1

V and VI, VI and VII and V and VII form pairs of metamers because they have different alkyl chains on either side of ethereal oxygen (-O-).