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Consider structures I to VII and answer the question: I. CH3 – CH2 – CH2 – CH2 – OH II. CHX3−CHX2−CH−CHX3.....|.......OH III. ...CHX3|CHX3−C−CHX3|..OH IV. CHX3−CH−CHX2−OH|........CHX3...... - Chemistry

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प्रश्न

Consider structures I to VII and answer the question:

I. CH3 – CH2 – CH2 – CH2 – OH
II. \[\begin{array}{cc}
\ce{CH3 - CH2 - CH - CH3}\\
\phantom{.....}|\\
\phantom{.......}\ce{OH}
\end{array}\]
III. \[\begin{array}{cc}
\phantom{...}\ce{CH3}\\
\phantom{}|\\
\ce{CH3 - C - CH3}\\
\phantom{}|\\
\phantom{..}\ce{OH}
\end{array}\]
IV. \[\begin{array}{cc}
\ce{CH3 - CH - CH2 - OH}\\
|\phantom{........}\\
\ce{CH3}\phantom{......}
\end{array}\]
V. CH3 – CH2 – O – CH2 – CH3
VI. CH3 – O – CH2 – CH2 – CH3
VII. \[\begin{array}{cc}
\ce{CH3 - O - CH - CH3}\\
\phantom{...}|\\
\phantom{......}\ce{CH3}
\end{array}\]

Identify the pairs of compounds which are functional group isomers.

टिप्पणी लिखिए

उत्तर

The compounds with the same molecular formula but different functional groups are said to be functional group isomers. 

Alcohols are found to be the functional isomers of ether. In the given structures, I, II, III, IV alcohol functional group is present and V, VI, VII contains ether functional group. Hence, I and V, I and VI, I and VII, II and V, II and VI, II and VII, III and V, III and VI etc are functional group isomers.

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Isomerism
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अध्याय 12: Organic Chemistry Some Basic Principles and Techniques - Multiple Choice Questions (Type - I) [पृष्ठ १५०]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 11
अध्याय 12 Organic Chemistry Some Basic Principles and Techniques
Multiple Choice Questions (Type - I) | Q 24 | पृष्ठ १५०

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\[\begin{array}{cc}
\ce{CH3 - CH - CH2 - CH3 and CH3 - CH2 - O - CH2 - CH3}\\|\phantom{...........................................}\\
\ce{OH}\phantom{.........................................}\end{array}\]


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\[\begin{array}{cc}\ce{^+OH}\\||\\
\ce{H - C - OH}\end{array}\]

\[\begin{array}{cc}\ce{OH}\phantom{.}\\|\phantom{...}\\
\ce{H - C^+ - OH}\end{array}\]


Consider structures I to VII and answer the question:

I. CH3 – CH2 – CH2 – CH2 – OH
II. \[\begin{array}{cc}
\ce{CH3 - CH2 - CH - CH3}\\
\phantom{.....}|\\
\phantom{.......}\ce{OH}
\end{array}\]
III. \[\begin{array}{cc}
\phantom{...}\ce{CH3}\\
\phantom{}|\\
\ce{CH3 - C - CH3}\\
\phantom{}|\\
\phantom{..}\ce{OH}
\end{array}\]
IV. \[\begin{array}{cc}
\ce{CH3 - CH - CH2 - OH}\\
|\phantom{........}\\
\ce{CH3}\phantom{......}
\end{array}\]
V. CH3 – CH2 – O – CH2 – CH3
VI. CH3 – O – CH2 – CH2 – CH3
VII. \[\begin{array}{cc}
\ce{CH3 - O - CH - CH3}\\
\phantom{...}|\\
\phantom{......}\ce{CH3}
\end{array}\]

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And 

\[\begin{array}{cc}
\phantom{.....................}\ce{CH3}\\
\phantom{................}/\\
\phantom{}\ce{CH3 - S - CH}\\
\phantom{...............}\backslash\\
\phantom{....................}\ce{CH3}
\end{array}\]


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