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Consider structures I to VII and answer the question: I. CH3 – CH2 – CH2 – CH2 – OH II. CHX3−CHX2−CH−CHX3.....|.......OH III. ...CHX3|CHX3−C−CHX3|..OH IV. CHX3−CH−CHX2−OH|........CHX3...... - Chemistry

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प्रश्न

Consider structures I to VII and answer the question:

I. CH3 – CH2 – CH2 – CH2 – OH
II. \[\begin{array}{cc}
\ce{CH3 - CH2 - CH - CH3}\\
\phantom{.....}|\\
\phantom{.......}\ce{OH}
\end{array}\]
III. \[\begin{array}{cc}
\phantom{...}\ce{CH3}\\
\phantom{}|\\
\ce{CH3 - C - CH3}\\
\phantom{}|\\
\phantom{..}\ce{OH}
\end{array}\]
IV. \[\begin{array}{cc}
\ce{CH3 - CH - CH2 - OH}\\
|\phantom{........}\\
\ce{CH3}\phantom{......}
\end{array}\]
V. CH3 – CH2 – O – CH2 – CH3
VI. CH3 – O – CH2 – CH2 – CH3
VII. \[\begin{array}{cc}
\ce{CH3 - O - CH - CH3}\\
\phantom{...}|\\
\phantom{......}\ce{CH3}
\end{array}\]

Identify the pairs of compounds that represents position isomerism.

टिप्पणी लिखिए

उत्तर

If two or more compounds differ in the position of substituent, functional group, or multiple bonds but molecular formula is same then these are said to be position isomers as they exhibit position isomerism. 

In the given structures, I and II, III and IV, VI and VII are found to be the position isomers.

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Isomerism
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अध्याय 12: Organic Chemistry Some Basic Principles and Techniques - Multiple Choice Questions (Type - I) [पृष्ठ १५०]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 11
अध्याय 12 Organic Chemistry Some Basic Principles and Techniques
Multiple Choice Questions (Type - I) | Q 25 | पृष्ठ १५०

संबंधित प्रश्न

Draw the cis and trans structures of hex-2-ene. Which isomer will have higher b.p. and why?


What is the relationship between the members of following pairs of structures? Are they structural or geometrical isomers or resonance contributors?

\[\begin{array}{cc}
\ce{D}\phantom{......}\ce{H}\\
\backslash\phantom{......}/\\
\ce{C = C}\\
\phantom{...}/\phantom{......}\backslash\phantom{...}\\\ce{H}\phantom{.......}\ce{D}
\end{array}\]

\[\begin{array}{cc}
\ce{D}\phantom{......}\ce{D}\\
\backslash\phantom{......}/\\
\ce{C = C}\\
\phantom{...}/\phantom{......}\backslash\phantom{...}\\\ce{H}\phantom{.......}\ce{H}\end{array}\]


Find out the type of isomerism exhibited by the following pair.


What type(s) of isomerism is(are) shown by [Co(NH3)4Br2]Cl?


Which of the following pairs are position isomers?

I. \[\begin{array}{cc}
\phantom{.......................}\ce{O}\\
\phantom{.......................}||\\
\ce{CH3 - CH2 - CH2 - CH2 - C - H}
\end{array}\]
II. \[\begin{array}{cc}
\phantom{.................}\ce{O}\\
\phantom{.................}||\\
\ce{CH3 - CH2 - CH2 - C - H}
\end{array}\]
III. \[\begin{array}{cc}
\ce{CH3 - CH2 - C - CH2 - CH3}\\
\phantom{}||\\
\phantom{}\ce{O}
\end{array}\]
IV. \[\begin{array}{cc}
\ce{CH3 - CH - CH2 - C - H}\\
\phantom{...}|\phantom{............}||\phantom{}\\
\phantom{...}\ce{CH3}\phantom{.........}\ce{O}\phantom{}
\end{array}\]

(i) I and II

(ii) II and III

(iii) II and IV

(iv) III and IV


Which of the following pairs are not functional group isomers?

I. \[\begin{array}{cc}
\phantom{.......................}\ce{O}\\
\phantom{.......................}||\\
\ce{CH3 - CH2 - CH2 - CH2 - C - H}
\end{array}\]
II. \[\begin{array}{cc}
\phantom{.................}\ce{O}\\
\phantom{.................}||\\
\ce{CH3 - CH2 - CH2 - C - H}
\end{array}\]
III. \[\begin{array}{cc}
\ce{CH3 - CH2 - C - CH2 - CH3}\\
\phantom{}||\\
\phantom{}\ce{O}
\end{array}\]
IV. \[\begin{array}{cc}
\ce{CH3 - CH - CH2 - C - H}\\
\phantom{...}|\phantom{............}||\phantom{}\\
\phantom{...}\ce{CH3}\phantom{.........}\ce{O}\phantom{}
\end{array}\]

(i) II and III

(ii) II and IV

(iii) I and IV

(iv) I and II


Consider structures I to VII and answer the question:

I. CH3 – CH2 – CH2 – CH2 – OH
II. \[\begin{array}{cc}
\ce{CH3 - CH2 - CH - CH3}\\
\phantom{.....}|\\
\phantom{.......}\ce{OH}
\end{array}\]
III. \[\begin{array}{cc}
\phantom{...}\ce{CH3}\\
\phantom{}|\\
\ce{CH3 - C - CH3}\\
\phantom{}|\\
\phantom{..}\ce{OH}
\end{array}\]
IV. \[\begin{array}{cc}
\ce{CH3 - CH - CH2 - OH}\\
|\phantom{........}\\
\ce{CH3}\phantom{......}
\end{array}\]
V. CH3 – CH2 – O – CH2 – CH3
VI. CH3 – O – CH2 – CH2 – CH3
VII. \[\begin{array}{cc}
\ce{CH3 - O - CH - CH3}\\
\phantom{...}|\\
\phantom{......}\ce{CH3}
\end{array}\]

Identify the pairs of compounds which are functional group isomers.


Compounds with same molecular formula but differing in their structures are said to be structural isomers. What type of structural isomerism is shown by

CH3 – S – CH2 – CH2 – CH3

And 

\[\begin{array}{cc}
\phantom{.....................}\ce{CH3}\\
\phantom{................}/\\
\phantom{}\ce{CH3 - S - CH}\\
\phantom{...............}\backslash\\
\phantom{....................}\ce{CH3}
\end{array}\]


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Reason (R): Position isomers differ in the position of functional group or a substituent.


Assertion (A): The compound cyclooctane has the following structural formula:

It is cyclic and has conjugated 8π-electron system but it is not an aromatic compound.

Reason (R): (4n + 2)π electrons rule does not hold good and ring is not planar.


Which of the following does NOT exhibit geometrical isomerism? 


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The correct stereochemical name of


How many structural isomers possible of the molecular formula C3H6O (excluding enol form)?


The number of acyclic structural isomers (including geometrical isomers) for pentene are ______.


Which of the following pairs of compounds are positional isomers?


Which of the following reactions will not produce a racemic product?


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