Question

Consider the reaction \[\ce{2A + 2B -> C + 2D}\], if concentration of A is doubled at constant [B], rate increases by a factor 4. If concentration B is doubled at constant [A] the rate is doubled. Rate law of the reaction is ____________.

विकल्प

• rate = k[A]² [B]

• rate = k[A] [B]²

• rate = k[A]² [B]²

• rate = k[A] [B]

Answer 1

Consider the reaction \[\ce{2A + 2B -> C + 2D}\], if concentration of A is doubled at constant [B], rate increases by a factor 4. If concentration B is doubled at constant [A] the rate is doubled. Rate law of the reaction is rate = k[A]² [B].