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Question
Consider the reaction \[\ce{2A + 2B -> C + 2D}\], if concentration of A is doubled at constant [B], rate increases by a factor 4. If concentration B is doubled at constant [A] the rate is doubled. Rate law of the reaction is ____________.
Options
rate = k[A]2 [B]
rate = k[A] [B]2
rate = k[A]2 [B]2
rate = k[A] [B]
MCQ
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Solution
Consider the reaction \[\ce{2A + 2B -> C + 2D}\], if concentration of A is doubled at constant [B], rate increases by a factor 4. If concentration B is doubled at constant [A] the rate is doubled. Rate law of the reaction is rate = k[A]2 [B].
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Rate of Reaction and Reactant Concentration
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