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प्रश्न
Construct an isosceles Δ ABC such that:
Base AC = 5 cm and base angle = 75°. Measure the other two sides of the triangle.
उत्तर
Steps of Construction:
We know that the base angles of an isosceles triangle are equal.
(i) Draw a line segment AC = 5cm.
(ii) At A and C, draw rays making an angle of 75° each which intersects each other at B.
∆ ABC is the required triangle.
On measuring the equal sides, each is 9.3 cm in length.
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संबंधित प्रश्न
Construct a ∆ABC such that:
BC = 4 cm, AC = 5 cm and AB = 3.5 cm
Construct a ∆ ABC such that:
BC = 6 cm, AC = 5.7 cm and ∠ACB = 75°
Construct a ∆ ABC such that:
AB = 6.5 cm, AC = 5.8 cm and ∠A = 45°
Construct a ∆ PQR such that:
QR = 4.4 cm, ∠R = 30° and ∠Q = 75°. Measure PQ and PR.
Construct an isosceles Δ ABC such that:
Base AB = 6.2 cm and base angle = 45°. Measure the other two sides of the triangle.
Construct an isosceles ∆ ABC such that:
AB = AC = 6.5 cm and ∠A = 60°
Construct an isosceles ∆ ABC such that:
One of the equal sides = 6 cm and vertex angle = 45°. Measure the base angles.
Construct a ∆ ABC such that AB = 6 cm, BC = 5.6 cm and CA = 6.5 cm. Inscribe a circle to this triangle and measure its radius.
Construct an isosceles ∆ MNP such that base MN = 5.8 cm, base angle MNP = 30°. Construct an incircle to this triangle and measure its radius.
Construct a ∆ PQR such that PQ = 6 cm, ∠QPR = 45° and angle PQR = 60°. Locate its incentre and then draw its incircle.
