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Construct the Right Angled Trianglepqr, Where M∠Q = 90°, Qr = 8 Cm and Pr = 10 Cm. - Mathematics

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प्रश्न

Construct the right angled ΔPQR, where m∠Q = 90°, QR = 8 cm and PR = 10 cm.

उत्तर

A rough sketch of ΔPQR is as follows.

The steps of construction are as follows.

1) Draw a line segment QR of length 8 cm.

2) At point Q, draw a ray QX making 90º with QR.

3) Taking R as centre, draw an arc of 10 cm radius to intersect ray QX at point P.

4) Join P to R. ΔPQR is the required right-angled triangle

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अध्याय 10: Practical Geometry - Exercise 10.5 [पृष्ठ २०३]

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एनसीईआरटी Mathematics [English] Class 7
अध्याय 10 Practical Geometry
Exercise 10.5 | Q 1 | पृष्ठ २०३

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