English

Construct the Right Angled Trianglepqr, Where M∠Q = 90°, Qr = 8 Cm and Pr = 10 Cm. - Mathematics

Advertisements
Advertisements

Question

Construct the right angled ΔPQR, where m∠Q = 90°, QR = 8 cm and PR = 10 cm.

Solution

A rough sketch of ΔPQR is as follows.

The steps of construction are as follows.

1) Draw a line segment QR of length 8 cm.

2) At point Q, draw a ray QX making 90º with QR.

3) Taking R as centre, draw an arc of 10 cm radius to intersect ray QX at point P.

4) Join P to R. ΔPQR is the required right-angled triangle

shaalaa.com
  Is there an error in this question or solution?
Chapter 10: Practical Geometry - Exercise 10.5 [Page 203]

APPEARS IN

NCERT Mathematics [English] Class 7
Chapter 10 Practical Geometry
Exercise 10.5 | Q 1 | Page 203
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×