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प्रश्न
`"d"/"dx" {"cosec"^-1 ((1 + "x"^2)/(2"x"))}` is equal to ____________.
विकल्प
`- 2/(1 + "x"^2), "x" ne 0`
`(2(1 + "x"))/(1 + "x"^2), "x" ne 0`
`(2 (1 - "x"^2))/((1 + "x"^2) abs (1 - "x"^2)), "x" ne pm 1, 0`
None of these
MCQ
रिक्त स्थान भरें
उत्तर
`"d"/"dx" {"cosec"^-1 ((1 + "x"^2)/(2"x"))}` is equal to `underline((2 (1 - "x"^2))/((1 + "x"^2) abs (1 - "x"^2)), "x" ne pm 1, 0)`.
shaalaa.com
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