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Ddxcosecxxddx{cosec-1(1+x22x)} is equal to ____________. -

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Question

`"d"/"dx" {"cosec"^-1 ((1 + "x"^2)/(2"x"))}` is equal to ____________.

Options

  • `- 2/(1 + "x"^2), "x" ne 0`

  • `(2(1 + "x"))/(1 + "x"^2), "x" ne 0`

  • `(2 (1 - "x"^2))/((1 + "x"^2) abs (1 - "x"^2)), "x" ne pm 1, 0`

  • None of these

MCQ
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Solution

`"d"/"dx" {"cosec"^-1 ((1 + "x"^2)/(2"x"))}` is equal to `underline((2 (1 - "x"^2))/((1 + "x"^2) abs (1 - "x"^2)), "x" ne pm 1, 0)`.

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