Advertisements
Advertisements
प्रश्न
Determine if the following numbers are in proportion:
33, 121, 9, 96
उत्तर
33, 121, 9, 96
`33/121=(33 ÷ 11)/(121 ÷ 11)=3/11;9/96=(9 ÷ 3)/(96 ÷ 3)=3/32`
Hence, 33:121::9:96 are not in proportion.
APPEARS IN
संबंधित प्रश्न
If `x/a = y/b = z/c` prove that `(2x^3 - 3y^3 + 4z^3)/(2a^3 - 3b^3 + 4c^3) = ((2x - 3y + 4z)/(2a - 3b + 4c))^3`
Find two numbers such that the mean proportional between them is 14 and third proportional to them is 112.
If `x/a = y/b = z/c`, show that `x^3/a^3 - y^3/b^3 = z^3/c^3 = (xyz)/(zbc).`
Find the third proportional to 5, 10
Write (T) for true and (F) for false in case of the following:
36 : 45 : : 80 : 100
Choose the correct statement:
If ax = by = cz; prove that `x^2/"yz" + y^2/"zx" + z^2/"xy" = "bc"/a^2 + "ca"/b^2 + "ab"/c^2`
If a, b, c are in continued proportion, prove that: `(1)/a^3 + (1)/b^3 + (1)/c^3 = a/(b^2c^2) + b/(c^2a^2) + c/(a^2b^2)`
10 books is to 15 books as 3 books is to 15 books
If 7 : 5 is in proportion to x : 25, then ‘x’ is