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प्रश्न
Differentiate the following with respect to x.
`(sqrtx + 1/sqrtx)^2`
योग
उत्तर
Let y = `(sqrtx + 1/sqrtx)^2`
`x + 1/x + 2 * sqrtx * 1/sqrtx`
y = `x + 1/x + 2`
`"dy"/"dx" = 1 - 1/x^2 + 0 = 1 - 1/x^2`
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Differentiation Techniques
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Differential Calculus - Exercise 5.5 [पृष्ठ ११८]
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