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प्रश्न
Differentiate the following w.r.t.x. :
y = x3 log x
योग
उत्तर
Let y = x3 log x
∴ `("d"y)/("d"x) = "d"/("d"x) [x^3 log x]`
= `x^3 "d"/("d"x) (logx) + (logx) "d"/("d"x) (x^3)`
= `x^3 (1/x) + (log x)(3x^2)`
= x2 + 3x2 log x
= x2 (1 + 3 log x)
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Derivative of Logarithmic Functions
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