Advertisements
Advertisements
प्रश्न
Distinguish between the following pair of compounds using the test given with brackets:
Dilute sulphuric acid and dilute hydrochloric acid (using barium chloride solution)
उत्तर
Sulphuric acid precipitates the insoluble sulphate of barium from the solution of barium chloride.
\[\ce{BaCl2 + H2SO4 -> BaSO4\downarrow + HCl}\]
\[\ce{BaCl2 + HCl -> No ppt formation}\]
Dilute HCl does not react with barium chloride solution, and thus, no precipitate is produced in the reaction.
APPEARS IN
संबंधित प्रश्न
State one relevant observation for given reactions:
Action of concentrated Sulphuric acid on hydrated copper sulfate
State the conditions required for the given reaction to take place:
Any two conditions for the conversion of sulphur dioxide to sulphur trioxide
Why is \[\ce{H2SO4}\] is not used as a drying agent for \[\ce{H2S}\]?
Name the following:
Products obtained by treating ferrous sulphide with dilute sulphuric acid.
Name the following:
The precipitate obtained by treating aqueous barium chloride with dilute sulphuric acid.
Name the following:
The precipitate obtained by treating carbon with hot concentrated sulphuric acid.
Give reason for the following:
When concentrated sulphuric acid is added to blue crystalline copper sulphate, it turns powdery white.
State your observation for the following case :
Paper soaked in potassium permanganate solution is introduced into a gas jar of sulphur dioxide.
Write balanced chemical equation to show :
The behavior of H2SO4 as an acid when it reacts with magnesium.
Write the observation for the following:
Decomposition of bicarbonates by dil. H2SO4
\[\ce{2NaHCO3 + H2SO4 -> Na2SO4 + 2H2O + 2CO2}\]
